(H x W) / (1.6 x 1.6) is the same as H/1.6 x W/1.6, and no, you always have to perform 3 operations each time, no matter the distribution of the multiplication/division. I was dividing both by 1.6 and then multiplying them together. You need to give me OK to edit your image and repost! Keep POTN alive and well with member support hpĬanon dSLR system, Olympus OM 35mm system, Bronica ETRSi 645 system, Horseman LS 4x5 system, Metz flashes, Dynalite studio lighting, and too many accessories to mention Most explanations are in terms of interference patterns generated by grates.where do you ever find that in photography apart from the generation of Newton ring?! Knowing where the angle vertex is positiioned at least at a high level concept would be much better than the concept of the angle with zero comprehension of the angular quanitifcatio0.n Maybe someone else can ad further enlightenment, within the context of photography. I ask, only to try to get my own understanding. I fully comprehend how any one of us may not fully understand a particular topic. The questions you ask are actually entire chapters in optics and imaging texts, and a couple of days of hands-on experimentation and classes to scratch the surface of the subject, and I don't have the time to give you the answers you really want. I'm sorry for the poor and limited explanations.
#APS C TO FULL FRAME CONVERSION HOW TO#
This explains how, for a telescope, how to match the resolution of the telescope to the sensor:
Remember that we can change the aperture, so if at higher f-numbers, we are likely over-sampling the image, and seeing lower resolution. For a telescope, it is the size of the lens or mirror. For a microscope, that is a combination of the objective and condenser numerical apertures. …ize-and-camera-resolutionĪs for the angle, that is a function of the lens aperture. Three pixels works because of Nyquist sampling: If the light spreads some angle (like two seconds of arc (- arbitrary amount, for discusion of concept only!) so that the spread at the sensor is defined by two seconds of arc, what should we use as the vertex so the spread distance can be determined based upon its distance from vertex of the angle to be calculation?! Without a defined vertex location, the replacement of 'three pixels' by 'two seconds of arc' is a meaningless value, worth less than 'three pixels'.because doubling the distance to the vertex makes the spread twice as large in linear terms even though the angle is the same.Įssentially, you are asking how to convert angular resolution to sensor resolution.
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